Optimal. Leaf size=361 \[ \frac{(d+e x)^{m+1} \left (a e m (a B e+A c d)-\sqrt{-a} \sqrt{c} \left (A \left (a e^2 (1-m)+c d^2\right )+a B d e m\right )\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d-\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} (m+1) \left (\sqrt{c} d-\sqrt{-a} e\right ) \left (a e^2+c d^2\right )}+\frac{(d+e x)^{m+1} \left (\sqrt{-a} \sqrt{c} \left (A \left (a e^2 (1-m)+c d^2\right )+a B d e m\right )+a e m (a B e+A c d)\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d+\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} (m+1) \left (\sqrt{-a} e+\sqrt{c} d\right ) \left (a e^2+c d^2\right )}-\frac{(d+e x)^{m+1} (a (B d-A e)-x (a B e+A c d))}{2 a \left (a+c x^2\right ) \left (a e^2+c d^2\right )} \]
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Rubi [A] time = 0.582754, antiderivative size = 359, normalized size of antiderivative = 0.99, number of steps used = 5, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {823, 831, 68} \[ \frac{(d+e x)^{m+1} \left (a e m (a B e+A c d)-\sqrt{-a} \sqrt{c} \left (a A e^2 (1-m)+a B d e m+A c d^2\right )\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d-\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} (m+1) \left (\sqrt{c} d-\sqrt{-a} e\right ) \left (a e^2+c d^2\right )}+\frac{(d+e x)^{m+1} \left (\sqrt{-a} \sqrt{c} \left (a A e^2 (1-m)+a B d e m+A c d^2\right )+a e m (a B e+A c d)\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d+\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} (m+1) \left (\sqrt{-a} e+\sqrt{c} d\right ) \left (a e^2+c d^2\right )}-\frac{(d+e x)^{m+1} (a (B d-A e)-x (a B e+A c d))}{2 a \left (a+c x^2\right ) \left (a e^2+c d^2\right )} \]
Antiderivative was successfully verified.
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Rule 823
Rule 831
Rule 68
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^m}{\left (a+c x^2\right )^2} \, dx &=-\frac{(d+e x)^{1+m} (a (B d-A e)-(A c d+a B e) x)}{2 a \left (c d^2+a e^2\right ) \left (a+c x^2\right )}-\frac{\int \frac{(d+e x)^m \left (-c \left (A c d^2+a A e^2 (1-m)+a B d e m\right )+c e (A c d+a B e) m x\right )}{a+c x^2} \, dx}{2 a c \left (c d^2+a e^2\right )}\\ &=-\frac{(d+e x)^{1+m} (a (B d-A e)-(A c d+a B e) x)}{2 a \left (c d^2+a e^2\right ) \left (a+c x^2\right )}-\frac{\int \left (\frac{\left (-a \sqrt{c} e (A c d+a B e) m-\sqrt{-a} c \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) (d+e x)^m}{2 a \left (\sqrt{-a}-\sqrt{c} x\right )}+\frac{\left (a \sqrt{c} e (A c d+a B e) m-\sqrt{-a} c \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) (d+e x)^m}{2 a \left (\sqrt{-a}+\sqrt{c} x\right )}\right ) \, dx}{2 a c \left (c d^2+a e^2\right )}\\ &=-\frac{(d+e x)^{1+m} (a (B d-A e)-(A c d+a B e) x)}{2 a \left (c d^2+a e^2\right ) \left (a+c x^2\right )}-\frac{\left (a e (A c d+a B e) m-\sqrt{-a} \sqrt{c} \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) \int \frac{(d+e x)^m}{\sqrt{-a}+\sqrt{c} x} \, dx}{4 a^2 \sqrt{c} \left (c d^2+a e^2\right )}+\frac{\left (a e (A c d+a B e) m+\sqrt{-a} \sqrt{c} \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) \int \frac{(d+e x)^m}{\sqrt{-a}-\sqrt{c} x} \, dx}{4 a^2 \sqrt{c} \left (c d^2+a e^2\right )}\\ &=-\frac{(d+e x)^{1+m} (a (B d-A e)-(A c d+a B e) x)}{2 a \left (c d^2+a e^2\right ) \left (a+c x^2\right )}+\frac{\left (a e (A c d+a B e) m-\sqrt{-a} \sqrt{c} \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) (d+e x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d-\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} \left (\sqrt{c} d-\sqrt{-a} e\right ) \left (c d^2+a e^2\right ) (1+m)}+\frac{\left (a e (A c d+a B e) m+\sqrt{-a} \sqrt{c} \left (A c d^2+a A e^2 (1-m)+a B d e m\right )\right ) (d+e x)^{1+m} \, _2F_1\left (1,1+m;2+m;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d+\sqrt{-a} e}\right )}{4 a^2 \sqrt{c} \left (\sqrt{c} d+\sqrt{-a} e\right ) \left (c d^2+a e^2\right ) (1+m)}\\ \end{align*}
Mathematica [A] time = 0.793603, size = 310, normalized size = 0.86 \[ \frac{(d+e x)^{m+1} \left (\frac{\sqrt{c} \left (a e m (a B e+A c d)-\sqrt{-a} \sqrt{c} \left (-a A e^2 (m-1)+a B d e m+A c d^2\right )\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d-\sqrt{-a} e}\right )}{a (m+1) \left (\sqrt{c} d-\sqrt{-a} e\right )}+\frac{\sqrt{c} \left (\sqrt{-a} \sqrt{c} \left (-a A e^2 (m-1)+a B d e m+A c d^2\right )+a e m (a B e+A c d)\right ) \, _2F_1\left (1,m+1;m+2;\frac{\sqrt{c} (d+e x)}{\sqrt{c} d+\sqrt{-a} e}\right )}{a (m+1) \left (\sqrt{-a} e+\sqrt{c} d\right )}+\frac{2 c (a (A e-B d+B e x)+A c d x)}{a+c x^2}\right )}{4 a c \left (a e^2+c d^2\right )} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.055, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( Bx+A \right ) \left ( ex+d \right ) ^{m}}{ \left ( c{x}^{2}+a \right ) ^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{c^{2} x^{4} + 2 \, a c x^{2} + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{{\left (c x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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